• Sep 24th 2006, 07:10 AM
Confuzzled?
When x is between 0 and 2pi
a) sinx=0.7

When theta is between negative pi and pi

a) 6sinthetacostheta-3costheta+2sintheta-1=0

When theta is between 0 and 2pi

b)3 cos^2theta-13costheta=sin^2theta-9

thanks in advance if you can help me:)
• Sep 24th 2006, 08:22 AM
Soroban
Hello, Confuzzled!

Quote:

When 0 ≤ x ≤ 2π

. . a) . sin x .= .0.7

You need a calculator for this one.

. . x .= .Inverse sine of (0.7) . .0.7754, 2.3662 radians.

Quote:

When -π ≤ θ ≤ π

. . a) . 6sinθcosθ - 3cosθ + 2sinθ - 1 .= .0

Factor: . 3cosθ(2sinθ - 1) + (2sinθ - 1) .= .0

Factor: . (2sinθ - 1)(3cosθ + 1) .= .0

We have: . 2sinθ - 1 .= .0 . . sinθ = 1/2 . . θ . .0.524, 2.618

. . . .and: . 3cosθ + 1 .= .0 . . cosθ = -1/3 . . θ . .1.911, -1.911

Quote:

When 0 ≤ θ ≤ 2π

. . b) . 3cos²θ - 13cosθ .= .sin²θ - 9

We have: . . . .3cos²θ - 13cosθ .= .1 - cos²θ - 9

. . .Then: . 4cos²θ - 13cosθ + 8 .= .0

This does not factor; we need the Quadratic Formula.
. . . . . . . . . . . . . . __
. . . . . . . . . .13 ± √41
. . cosθ . = . ----------- . . 2.4254, 0.8246
. . . . . . . . . . . . 8

We have: . cosθ .= .2.4254 . . . no solution!

. . . .and: . cosθ .= .0.8246 . . θ . .0.6013, 5.6819 radians

• Sep 25th 2006, 01:35 PM
Confuzzled?
Thanks for your help. I’ve attempted to answer the following questions but it seems that I get many answers and I’m not sure if I’m doing it right. Could u help me with the following?:

For theta being between 0 and 360
a) sin^2theta=4cos^2theta

For theta being between pi and 2pi
b) 4cos^2theta=3
• Sep 25th 2006, 02:56 PM
Soroban
Hello again, Confuzzled!

Quote:

a) sin²θ = 4cos²θ . . 0° < θ < 360°

Divide both sides by cos²θ:

. . . sin²θ
. . . ------- .= .4
. . . cos²θ

. . . tan²θ .= .4

. . . .tanθ .= .±2

. . . . . . θ . .63.4°, 116.6°, 243.4°, 296.6°

Quote:

b) 4cos²θ = 3 . . π < θ < 2π

. . . . . . . . . . . . . . . .3
We have: . cos²θ .= .---
. . . . . . . . . . . . . . . .4
. . . . . . . . . . . . . . . . . _
. . . . . . . . . . . . . . . . .√3
Then: . . . . cosθ .= . ± ---
. . . . . . . . . . . . . . . . . 2

Therefore: . θ .= .7π/6, 11π/6