Find the area of the minor segment formed on an arc of length 36cm drawn on a circle of radius 50cm.

Chord length = 2rsin(theta/2)

2 * 50sin(theta/2) = 36

theta = 0.7365

Area of segment = 0.5r^2(theta-sintheta)

= 81.01cm^2

Correct answer = 75.77cm^2