prove each identity so L.S. = R.S. 1) sin x (divided by) 2 = 1-cosx(divided by)2 (right side of equation is all under square root sign)
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have you tried using the trig identity, (cosx)^2 + (sinx)^2 = 1? also is that (1-cosx)/2 or 1-cosx/2?
i dont think that identity applys to this one does it? it is just the square root of 1-cos(theta) all over 2 = sin (theta) over 2 sin(theta) = 1-cos(theta) <- right side is all under a square root sign 2 2 hope that helps thanks
yea i thats what i mean both sides are equal
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