How do I solve this? What is the answer? sin x/2= (square root 3)/2 , -pi<x<pi (this is the range given) (I had no idea how to put a squre root symbol of the 3...)
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Originally Posted by jcfulton How do I solve this? What is the answer? sin x/2= (square root 3)/2 , -pi<x<pi (this is the range given) (I had no idea how to put a squre root symbol of the 3...) hint: $\displaystyle \sin (?) = \frac {\sqrt{3}}2$, what is $\displaystyle ?$?
sin 60 degrees is (square root 3)/2, therefore the answer is 120 degrees, since the angle is x/2.
sin of 60 degrees is (square root 3)/2..........or pi/3........where do I go from here?
sin x = (square root 3)/2 means that x is 60 degrees. sin x/2 = (square root 3)/2 means that x is 120....120/2 = 60
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