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Math Help - Trig help... (Prof's answer).

  1. #1
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    Trig help... (Prof's answer).

    Hey guys... I logged on today only to find my other thread full of a bunch of arguing and it was also locked. I thought I'd post my Prof's reply for you guys to see what, exactly we are doing.

    Here's what my prof. had to say...
    Your question is a good one. We must change the right side of the
    eqution into a fraction. Yes, we need to add (or subtract)
    1/sin^2(theta) - 1
    So we need to have the same denominator to get
    1/sin^2(theta) - sin^2(theta)/sin^2(theta)
    Together we form the quotient [1 - sin^2(theta)] / sin^2(theta)
    At this point you will have one quotient equaling another quotient, so
    you can do the reciprocal to both sides of the equation; and then take
    the square root on both sides.

    -Tom

    PS: Here was my original post...

    http://www.mathhelpforum.com/math-help/21282-post1.html
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  2. #2
    MHF Contributor
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    Yes I locked the thread because it was becoming too heated. I hope your question is answered.
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  3. #3
    Grand Panjandrum
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    Quote Originally Posted by TomCat View Post
    Hey guys... I logged on today only to find my other thread full of a bunch of arguing and it was also locked. I thought I'd post my Prof's reply for you guys to see what, exactly we are doing.

    [snip]

    PS: Here was my original post...

    http://www.mathhelpforum.com/math-help/21282-post1.html

    I have cleaned up the original thread and you should now be able to
    follow the gist of what is there without the distractions.

    RonL
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