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Thread: trigonometry equation

  1. November 3rd 2008, 02:21 PM #1
    jcfulton
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    Question trigonometry equation

    How do I solve this? What is the answer?

    tan3x=1, -pi/2<x<pi (this is the range that was given)
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  2. November 3rd 2008, 03:29 PM #2
    Soroban
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    Hello, jcfulton!

    Solve: . \tan3x\:=\:1 \qquad -\frac{\pi}{2} \,< \,x\,<\,\pi

    We know that: . \tan\tfrac{\pi}{4} \,=\,1 . . . and there are other angles, right?


    We have: . \tan3x \:=\:1

    Hence: . 3x \;=\;\text{-}\frac{3\pi}{4},\:\frac{\pi}{4},\;\frac{5\pi}{4},\ :\frac{9\pi}{4}

    Therefore: . x \;=\;\text{-}\frac{\pi}{4},\:\frac{\pi}{12},\:\frac{5\pi}{12}, \:\frac{3\pi}{4}
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