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Solve for 2sinx+ cos2x=2sin^2x-1 for 0< and equals x < and equals 2 ?
Thanks in advance! Urgent!!
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Arrange your equation and you will have it in the form of:
Then you can use the quadratic formula.
I got 4sin^2x-sinx+2=0
do i just solve x? I don't have to consider sin?
You solve the quadratic taking sin(x) as the variable and then you find x with
x = arcsin(sin(x)) there can be 2 solutions.
How do you when to use arcsin or when to use sin?
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