How in the world do I find the missing parts of the triangle ABC if a = 12, b = 19, and A = 82 deg's?
Thanks very much
////a//.\
////a/\.\\b
a//./____\
.........c
a = 12, b = 19, and A (opposite a) = 82 deg's
remember that $\displaystyle \frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}$
now you can easily solve for B.
Once you have B you know that A+B+C = 180 so you can get C and finally use C and the law of sines to get c
let me know if you need more help
The reason is that the problem is not clearly stated. There is no way that the angle opposite a is 82 degrees. It can only be between a and b (I would have called that angle C as it is opposite c) Try it again this way and you will get the answer.