Missing parts of triangle

• July 12th 2005, 04:17 PM
Justardms
Missing parts of triangle help
How in the world do I find the missing parts of the triangle ABC if a = 12, b = 19, and A = 82 deg's?

Thanks very much
• July 12th 2005, 09:07 PM
Math Help
Law of sines

////a/
/.\
////a/\.\\b
a//./____\
.........
c

a = 12, b = 19, and A (opposite a) = 82 deg's

remember that $\frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}$

now you can easily solve for B.

Once you have B you know that A+B+C = 180 so you can get C and finally use C and the law of sines to get c

let me know if you need more help
• July 13th 2005, 06:22 AM
Justardms