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Math Help - Trigonometry: Prove the Identity

  1. #1
    Member looi76's Avatar
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    Trigonometry: Prove the Identity

    \sin\theta\sec\theta\cot\theta \equiv 1

    \d{L}\d{H}\d{S} = \sin\theta\sec\theta\cot\theta

    = \sin\theta \times \frac{1}{\cos\theta} \times \frac{\cos\theta}{\sin\theta}

    After this step I donno what to do. I should proved that sin\theta\sec\theta\cot\theta is equal to 1, can anyone please help me!

    Thnx in advance!
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  2. #2
    Moo
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    Hello !

    Long time no see !
    Quote Originally Posted by looi76 View Post
    \sin\theta\sec\theta\cot\theta \equiv 1

    \d{L}\d{H}\d{S} = \sin\theta\sec\theta\cot\theta

    = \sin\theta \times \frac{1}{\cos\theta} \times \frac{\cos\theta}{\sin\theta}

    After this step I donno what to do. I should proved that sin\theta\sec\theta\cot\theta is equal to 1, can anyone please help me!

    Thnx in advance!
    Well, you're near to it

    \sin\theta \times \frac{1}{\cos\theta} \times \frac{\cos\theta}{\sin\theta}=\sin \theta \times \frac{1}{\cos \theta} \times \cos \theta \times \frac{1}{\sin \theta}

    Group it : =\sin \theta \times \frac{1}{\sin \theta} \times \cos \theta \times \frac{1}{\cos \theta}

    doesn't it simplify ?
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  3. #3
    Member looi76's Avatar
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    Quote Originally Posted by Moo View Post
    Hello !

    Long time no see !

    Well, you're near to it

    \sin\theta \times \frac{1}{\cos\theta} \times \frac{\cos\theta}{\sin\theta}=\sin \theta \times \frac{1}{\cos \theta} \times \cos \theta \times \frac{1}{\sin \theta}

    Group it : =\sin \theta \times \frac{1}{\sin \theta} \times \cos \theta \times \frac{1}{\cos \theta}

    doesn't it simplify ?
    Thanks for making it CLEAR!

    You remember me , Now, I'm in the University!
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