If sec^2(x) – 1 = sin(x) , which one of the following is a possible value for x?
how do you do this?
Thanks in advance. I don't get the sin,cosine rules so please help.! =)
The choices are
a) -
b)=
c) 0
d)
e)
thanks in advance!
If sec^2(x) – 1 = sin(x) , which one of the following is a possible value for x?
how do you do this?
Thanks in advance. I don't get the sin,cosine rules so please help.! =)
The choices are
a) -
b)=
c) 0
d)
e)
thanks in advance!
see, by inspection, 0 works.
note that the left hand side (which is actually) is an even function, so if (a) and (b) don't work, (d) and (e) would give the same answer and hence not work either. (c) being 0 catches your eye though, and i would test that first, and what do you know, it worked!
doing this with the algebra would be a bit more complicated and time consuming. so just do the check. you have to check at most 3 values, which you can do pretty quickly if you memorized the trig values for the special angles.