I have homework where i need to do the following:
3. For what values of t on the interval [0,2π] is: a. sin(t) = -1/2
b. tan(t) = -√3
*in part 'b' the symbol is a square root, meaning the negative square root of 3*
I think it can be solved using the unit circle (..?) but I can't figure it out.
I know that sin pi/6 is 1/2 and tan pi/3 is the square root of 3.
I understand what you said.
My problem is the negative signs are throwing me off.
Would the sine graph be 11π/6 and 7π/6 ??
And the tan graph would be 2π/3 and 5π/3 ??
If not i am truly lost.