# Simplify Trig

• Oct 15th 2008, 08:32 AM
gearshifter
Simplify Trig
Please take a look at the attached question, thank you!
• Oct 15th 2008, 09:26 AM
Chop Suey
Recall that:
$\tan^2{x} = \sec^2{x} - 1$

Notice that $1-\sec^2{x} = -(\sec^2{x}-1)$

You end up with $-\cot{x}\sin{x}$...Remember that $\cot{x} = \frac{\cos{x}}{\sin{x}}$