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Math Help - law of sines

  1. #1
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    Exclamation law of sines

    Beta=27.5
    upsidedown theada=54.5
    a= 9.27

    find c, b, and theda....
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  2. #2
    MHF Contributor
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    Quote Originally Posted by Peyton Sawyer View Post
    Beta=27.5
    upsidedown theada=54.5
    a= 9.27

    find c, b, and theda....
    Let me guess:
    There is a triangle ABC where
    a = BC = 9.27
    b = AC
    c = AB
    beta = angle B = 27.5 degrees
    upsidedown theta (phi?) = angle A = 54.5 degrees
    theta = angle C

    If my guess is right, then,

    theta = 180 -27.5 -54.5 = 98 degrees -----------answer

    By Law of Sines,
    9.27 /sin(54.5deg) = b /sin(27.5deg)
    Multiply both sides by sin(27.5deg),
    (9.27*sin(27.5deg) /sin(54.5deg) = b
    b = 5.26 -------answer.

    By Law pof Sines again,
    9.27 /sin(54.5deg) = c /sin(98deg)
    Multiply both sides by sin(98deg),
    (9.27*sin(98deg) /sin(54.5deg) = c
    c = 11.28 -------answer.
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