Beta=27.5
upsidedown theada=54.5
a= 9.27
find c, b, and theda....
Let me guess:
There is a triangle ABC where
a = BC = 9.27
b = AC
c = AB
beta = angle B = 27.5 degrees
upsidedown theta (phi?) = angle A = 54.5 degrees
theta = angle C
If my guess is right, then,
theta = 180 -27.5 -54.5 = 98 degrees -----------answer
By Law of Sines,
9.27 /sin(54.5deg) = b /sin(27.5deg)
Multiply both sides by sin(27.5deg),
(9.27*sin(27.5deg) /sin(54.5deg) = b
b = 5.26 -------answer.
By Law pof Sines again,
9.27 /sin(54.5deg) = c /sin(98deg)
Multiply both sides by sin(98deg),
(9.27*sin(98deg) /sin(54.5deg) = c
c = 11.28 -------answer.