Given that sin q= a+b and cos q = a- b, (a) find the value of a^2+ b^2
Last edited by maybeline9216; Oct 8th 2008 at 03:38 AM. Reason: to delete something
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Originally Posted by maybeline9216 Given that sin q= a+b and cos q = a- b, (a) find the value of a^2+ b^2 Is that really a^2 +b^2 ? Should it not be a^2 -b^2 ?
Originally Posted by ticbol Is that really a^2 +b^2 ? Should it not be a^2 -b^2 ? i really have no idea but that is wad the question paper wrote.....
$\displaystyle \sin ^2 (x) = a^2 + 2ab + b^2 \;\& \;\cos ^2 (x) = a^2 - 2ab + b^2 $ $\displaystyle 1 = \sin ^2 (x) + \cos ^2 (x) = 2a^2 + 2b^2 $
Originally Posted by Plato $\displaystyle \sin ^2 (x) = a^2 + 2ab + b^2 \;\& \;\cos ^2 (x) = a^2 - 2ab + b^2 $ $\displaystyle 1 = \sin ^2 (x) + \cos ^2 (x) = 2a^2 + 2b^2 $ Thanks a lot!!!
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