Given that cot q=-t, t>0 and 0° ≤q≤180° , find, in terms of t,

(a) cosec q

(b) tan(-q)

(c) sin(90°-q )

for(b) is it -(-1/t) = -(1/-t) ?? im kinda confused....

also can anyone tell me how to derive the following formulas from the four quadrants mtd....(as i dun want to memorise the formulas)

1) cos(-x)=cos x

2) tan(-x) = -tan x

3)sin(90°-x)=cos x