# Thread: Trig Equation - HELP!!!

1. ## Trig Equation - HELP!!!

1+sin^2x=3sinxcosx

Could someone please help me solve this!!

2. 1+sin^2x=3sinxcosx

$\displaystyle \Rightarrow \sin^2{x} + \cos^2{x} + \sin^2{x} = 3\sin{x}\cos{x}$

$\displaystyle \Rightarrow 2\sin^2{x} - 3\sin{x}\cos{x} + \cos^2{x} = 0$

You should see that this is factorable.

3. sorry but how does 1+sin^2 x = sin^2 x + cos^2 x + sin^2 x?

4. I used the Pythagorean identity:
$\displaystyle \sin^2{x} + \cos^2{x} = 1$