1+sin^2x=3sinxcosx Could someone please help me solve this!!
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1+sin^2x=3sinxcosx $\displaystyle \Rightarrow \sin^2{x} + \cos^2{x} + \sin^2{x} = 3\sin{x}\cos{x}$ $\displaystyle \Rightarrow 2\sin^2{x} - 3\sin{x}\cos{x} + \cos^2{x} = 0$ You should see that this is factorable.
sorry but how does 1+sin^2 x = sin^2 x + cos^2 x + sin^2 x?
I used the Pythagorean identity: $\displaystyle \sin^2{x} + \cos^2{x} = 1$
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