How can I find angle v in this figure?
Info:
AO=OB=OP=OC=6370 km
Drop a perpendicular from $\displaystyle C$ onto $\displaystyle OS$, call the new point at the foot of the perp. $\displaystyle Q$.Originally Posted by Neffets...:P
Now look at $\displaystyle \triangle OCQ$ you know $\displaystyle \angle QOC$, and $\displaystyle OC$, so you can find $\displaystyle OQ$ and $\displaystyle CQ$ using the $\displaystyle \sin$ and $\displaystyle \cos$ of $\displaystyle \angle QOC$ and $\displaystyle OC$.
Now switch attention to $\displaystyle \triangle CQS$. You know $\displaystyle SO$ and $\displaystyle OQ$, so you know $\displaystyle QS$. You already know $\displaystyle CQ$, so Pythagoras's theorem will now finish the problem.
RonL
I forgot:Originally Posted by CaptainBlack
Extent the tangent at $\displaystyle C$ to meet $\displaystyle OS$ at $\displaystyle T$, then $\displaystyle \triangle OCQ$ is similar to $\displaystyle \triangle CQT$. This will allow you to find $\displaystyle \angle CPS$, and you already have enough information to fins $\displaystyle \angle PSC$ which will allow you to find angle at $\displaystyle v$
RonL