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Math Help - Tricky triogonometri...

  1. #1
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    Tricky triogonometri...

    How can I find angle v in this figure?

    Info:

    AO=OB=OP=OC=6370 km
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  2. #2
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    Tricky with the figure missing?
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  3. #3
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    continues....

    PS=20240 km
    CP = 2780 km

    Thanks for all answers
    Attached Thumbnails Attached Thumbnails Tricky triogonometri...-gash.jpg  
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  4. #4
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    Quote Originally Posted by Neffets...:P
    PS=20240 km
    CP = 2780 km

    Thanks for all answers
    The key is that \angle POC=(arcCP)/OC=2780/6370 radian.

    The rest is just fiddly trig.
    Last edited by CaptainBlack; August 26th 2006 at 08:49 AM.
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  5. #5
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    thanks

    thanks mate! I think i'll manage it all now...



    You guys are GREAT!
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  6. #6
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    need more help...

    i have tried a lot, but i have not been able to find the answer!

    CP is a part of a circle...
    the angle is on a tangent.

    Can you guys show me how you find the answer?
    I know I seem a bit stupid, but...

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  7. #7
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    Quote Originally Posted by Neffets...:P
    i have tried a lot, but i have not been able to find the answer!

    CP is a part of a circle...
    the angle is on a tangent.

    Can you guys show me how you find the answer?
    I know I seem a bit stupid, but...

    Drop a perpendicular from C onto OS, call the new point at the foot of the perp. Q.

    Now look at \triangle OCQ you know \angle QOC, and OC, so you can find OQ and CQ using the \sin and \cos of \angle QOC and OC.

    Now switch attention to \triangle CQS. You know SO and OQ, so you know QS. You already know CQ, so Pythagoras's theorem will now finish the problem.

    RonL
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  8. #8
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    Quote Originally Posted by CaptainBlack
    Drop a perpendicular from C onto OS, call the new point at the foot of the perp. Q.

    Now look at \triangle OCQ you know \angle QOC, and OC, so you can find OQ and CQ using the \sin and \cos of \angle QOC and OC.

    Now switch attention to \triangle CQS. You know SO and OQ, so you know QS. You already know CQ, so Pythagoras's theorem will now finish the problem.

    RonL
    I forgot:

    Extent the tangent at C to meet OS at T, then \triangle OCQ is similar to \triangle CQT. This will allow you to find \angle CPS, and you already have enough information to fins \angle PSC which will allow you to find angle at v

    RonL
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  9. #9
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    The attached scan shows all the relevant dimensions and angles filled
    in on the diagram.

    RonL
    Attached Thumbnails Attached Thumbnails Tricky triogonometri...-gash.jpg  
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  10. #10
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    Talking Thanks Captain!

    This forum is great! Now I can finally get help when I'm in a tricky situation...
    Thanks a lot Captain Black!!!! :-D :-D

    I couldn't find the answer with your first explanation, so I'm glad you did remember the rest...


    Neffets...:P
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