How can I find angle v in this figure?

Info:

AO=OB=OP=OC=6370 km

Printable View

- Aug 26th 2006, 07:24 AMNeffets...:PTricky triogonometri...
How can I find angle v in this figure?

Info:

AO=OB=OP=OC=6370 km - Aug 26th 2006, 07:25 AMGlaysher
Tricky with the figure missing?

- Aug 26th 2006, 07:26 AMNeffets...:Pcontinues....
PS=20240 km

CP = 2780 km

Thanks for all answers :D - Aug 26th 2006, 07:43 AMCaptainBlackQuote:

Originally Posted by**Neffets...:P**

The rest is just fiddly trig. - Aug 26th 2006, 07:54 AMNeffets...:Pthanks
thanks mate! I think i'll manage it all now...

:D :D :D :D

You guys are GREAT! - Aug 26th 2006, 11:48 PMNeffets...:Pneed more help...
:mad: i have tried a lot, but i have not been able to find the answer!

CP is a part of a circle...

the angle is on a tangent.

Can you guys show me how you find the answer?

I know I seem a bit stupid, but...

:D :D - Aug 27th 2006, 12:01 AMCaptainBlackQuote:

Originally Posted by**Neffets...:P**

Now look at $\displaystyle \triangle OCQ$ you know $\displaystyle \angle QOC$, and $\displaystyle OC$, so you can find $\displaystyle OQ$ and $\displaystyle CQ$ using the $\displaystyle \sin$ and $\displaystyle \cos$ of $\displaystyle \angle QOC$ and $\displaystyle OC$.

Now switch attention to $\displaystyle \triangle CQS$. You know $\displaystyle SO$ and $\displaystyle OQ$, so you know $\displaystyle QS$. You already know $\displaystyle CQ$, so Pythagoras's theorem will now finish the problem.

RonL - Aug 27th 2006, 04:22 AMCaptainBlackQuote:

Originally Posted by**CaptainBlack**

Extent the tangent at $\displaystyle C$ to meet $\displaystyle OS$ at $\displaystyle T$, then $\displaystyle \triangle OCQ$ is similar to $\displaystyle \triangle CQT$. This will allow you to find $\displaystyle \angle CPS$, and you already have enough information to fins $\displaystyle \angle PSC$ which will allow you to find angle at $\displaystyle v$

RonL - Aug 27th 2006, 07:55 AMCaptainBlack
The attached scan shows all the relevant dimensions and angles filled

in on the diagram.

RonL - Aug 28th 2006, 07:44 AMNeffets...:PThanks Captain!
This forum is great! Now I can finally get help when I'm in a tricky situation...

Thanks a lot Captain Black!!!! :-D :-D

I couldn't find the answer with your first explanation, so I'm glad you did remember the rest...

Neffets...:P