Originally Posted by

**ticbol** I don't know your textbook's explanation but it could be like this.

You must draw the figure so that you can see approximately the position of the R.

For the horizontal components, going West is negative and going East is positive.

For the vertical components, going North is positive and going South is negative.

Summation of horizontal components.

H = -23.75sin(56.14deg) +48.61sin(33.86deg) = 7.36178 lbs ----positive, so going East

Summation of vertical components,

V = -23.75cos(56.14deg) -48.61cos(33.86deg) = -53.59850 lbs ----negative, so going South.

Meaning, the resultant R is going S some degrees E.

This "some degrees", or theta, is arctan(H/V)

Since you can see the figure, then disregard the signs of H and V. Remember that the signs are only for directions. Since you know already that R is due SE, just use the absolute values of the H and V-----or their positive values.

So,

theta = arctan(7.36178 /53.59850) = 7.82067 degrees

Therefore, the bearing of R is S 7.82deg E --------answer.