Use law of sines. Given a triangle ABC, side a is opposite angle A, side b is opposite angle B, side c is opposite angle C, then Law of Sines state that:
ok thank you very much. i also had some trouble with another problem. its given sides are BC 160, AD 270, and DC 190. it also has angles ADC 75 degrees and angle BCD is 90 degrees. i started by tryin to cut it to make two triangles. my separation was from angle B to D. which left me with triangles ABD and BCD. did i start off correctly?