your solution is correct, you were just a little sloppy with your work ...
sin(30 deg) = 4.7/x
x = 1/2 I think you meant sin(30) = 1/2
4.7/(1/2) = 9.4 miles
An airplane, flying at an altitude of y = 4.7 miles, is on a flight path that passes directly over an observer (see figure). If θ is the angle of elevation from the observer to the plane, find the distance from the observer to the plane for each value of θ.
theta = 30 degrees
I just want to know if this is the right way to solve this problem:
sin(30 deg) = 4.7/x
x = 1/2
4.7/(1/2) 9.4 miles
Thanks
For a great visual explanation of similar examples, check out Mathematics.com.au - Angles Of Elevation && Depression
The lesson is fully narrated as well so is very easy to understand.