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Math Help - [SOLVED] Trig problem help please?

  1. #1
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    Question [SOLVED] Trig problem help please?

    find the value of B given that:

    Tan(3B - 4) = 1/Cot(5B - 8)


    i do not know the steps to do this problem. i've tried to multiply tan and cot together but the answer wasn't correct
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by something3k View Post
    find the value of B given that:

    Tan(3B - 4) = 1/Cot(5B - 8)


    i do not know the steps to do this problem. i've tried to multiply tan and cot together but the answer wasn't correct
    hint: \frac 1{\cot x} = \tan x

    and note that the period of tan(x) is \pi
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  3. #3
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    Quote Originally Posted by Jhevon View Post
    hint: \frac 1{\cot x} = \tan x

    and note that the period of tan(x) is \pi

    i am sorry i do not understand what you are trying to tell me o_o can you please explain because i am stuck at the hint
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by something3k View Post
    i am sorry i do not understand what you are trying to tell me o_o can you please explain because i am stuck at the hint
    what you have is \tan (3B - 4) = \tan (5B - 8)

    now what does B have to be? (and remember tangent is periodic, there are infinitely many answers!)
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  5. #5
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    Hello, something3k!


    Theorem: .If \tan A = \tan B, then A \:=\:B + \pi n .for some integer n.



    Solve for \theta\!:\;\;\tan(3\theta - 4) \:=\: \frac{1}{\cot(5\theta - 8)}

    We have: . \tan(3\theta - 4) \;=\;\tan(5\theta - 8)

    Then: . 3\theta - 4 \;=\;5\theta-8 + \pi n

    . . . 2\theta \;=\;4 + \pi n \quad\Rightarrow\quad \boxed{\theta \:=\:2 + \frac{\pi}{2}n}

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  6. #6
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    Quote Originally Posted by Jhevon View Post
    what you have is \tan (3B - 4) = \tan (5B - 8)

    now what does B have to be? (and remember tangent is periodic, there are infinitely many answers!)

    OOHHHH I GET IT OMG IM SO SLOW THANKS YOUU
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  7. #7
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    thanks you guys, i got it now thanks so much yay
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