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Math Help - Trigonometric ratio...

  1. #1
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    Trigonometric ratio...

    Hi, I was wondering if someone could help me with this trigonometric ratio. I can't solve it using the identities...I end up going in circles or obtain, rather, weird values.
    3cot^2x = 1


    Thanks in advance!
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by storage1k View Post
    Hi, I was wondering if someone could help me with this trigonometric ratio. I can't solve it using the identities...I end up going in circles or obtain, rather, weird values.
    3cot^2x = 1


    Thanks in advance!
    You are looking for values of x, right? We know that
    cot(x) = \frac{1}{tan(x)}
    so

    3~cot^2(x) = 1

    \frac{3}{tan^2(x)} = 1

    tan^2(x) = 3
    and I'll let you take it from there.

    -Dan
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  3. #3
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    tan x = +/- sqrt(3), I believe?

    Man...I dismissed this answer early on thinking that it'd be a silly way to solve it. No clue why that thought even existed. Thank you very much!
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