# Math Help - Trigonometric ratio...

1. ## Trigonometric ratio...

Hi, I was wondering if someone could help me with this trigonometric ratio. I can't solve it using the identities...I end up going in circles or obtain, rather, weird values.
3cot^2x = 1

Thanks in advance!

2. Originally Posted by storage1k
Hi, I was wondering if someone could help me with this trigonometric ratio. I can't solve it using the identities...I end up going in circles or obtain, rather, weird values.
3cot^2x = 1

Thanks in advance!
You are looking for values of x, right? We know that
$cot(x) = \frac{1}{tan(x)}$
so

$3~cot^2(x) = 1$

$\frac{3}{tan^2(x)} = 1$

$tan^2(x) = 3$
and I'll let you take it from there.

-Dan

3. tan x = +/- sqrt(3), I believe?

Man...I dismissed this answer early on thinking that it'd be a silly way to solve it. No clue why that thought even existed. Thank you very much!