Hi, I was wondering if someone could help me with this trigonometric ratio. I can't solve it using the identities...I end up going in circles or obtain, rather, weird values.
3cot^2x = 1
Hi, I was wondering if someone could help me with this trigonometric ratio. I can't solve it using the identities...I end up going in circles or obtain, rather, weird values.
3cot^2x = 1
Thanks in advance!
You are looking for values of x, right? We know that
$\displaystyle cot(x) = \frac{1}{tan(x)}$
so
$\displaystyle 3~cot^2(x) = 1$
$\displaystyle \frac{3}{tan^2(x)} = 1$
$\displaystyle tan^2(x) = 3$
and I'll let you take it from there.