Does anyone have any ideas or tips how to solve these two, I'm really running out of time

Results 1 to 5 of 5

- September 15th 2008, 07:11 AM #1

- Joined
- Sep 2008
- Posts
- 6

## Please help

Hello. I'm having trouble with the 2 last calculus exercises witch I just can't solve. If someone would please tell me how to solve these two:

1) 1-sinx -cosx +sin2x+cos2x=0

2)log(2 below) (4^(x+1)+4) * log(2below) (4^(x)´+1)=log(1/square root of 2 below) (square root of 1/8)

Thanks to everyone who can help me!!!

- September 15th 2008, 09:48 AM #2

- Joined
- Sep 2008
- Posts
- 6

- September 15th 2008, 09:54 AM #3

- Joined
- May 2006
- From
- Lexington, MA (USA)
- Posts
- 12,026
- Thanks
- 845

- September 15th 2008, 10:14 AM #4

- Joined
- May 2006
- From
- Lexington, MA (USA)
- Posts
- 12,026
- Thanks
- 845

- September 15th 2008, 10:26 AM #5

- Joined
- Sep 2008
- Posts
- 6