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Math Help - finding the function value

  1. #1
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    finding the function value

    Construct an appropriate triangle to complete the table. (0 ≤ θ ≤ 90, 0 ≤ θ ≤ π / 2)


    (deg) 120


    (rad) 2pi / 3

    Function Value ?


    OK, I found the degrees which was 2pi / 3 radians (180/ pi radians) = 120

    but now how do I find the function value?
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  2. #2
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    Quote Originally Posted by robasc View Post
    Construct an appropriate triangle to complete the table. (0 ≤ θ ≤ 90, 0 ≤ θ ≤ π / 2)


    (deg) 120


    (rad) 2pi / 3

    Function Value ?


    OK, I found the degrees which was 2pi / 3 radians (180/ pi radians) = 120

    but now how do I find the function value?
    Do you have to calculate basic trignometric function for this value??

    \sin \frac{2 \pi}{3}= \sin 120^\circ  = \frac{\sqrt{3}}{2}

    \cos \frac{2 \pi}{3}= \cos 120^\circ  = \frac{-1}{2}

    \tan \frac{2 \pi}{3}= \tan 120^\circ  = - \sqrt{3}

    \csc \frac{2 \pi}{3}= \csc 120^\circ  = \frac{2}{\sqrt{3}}

    \sec \frac{2 \pi}{3}= \sec 120^\circ  = - 2

    \cot \frac{2 \pi}{3}= \cot 120^\circ  = -\frac{1}{\sqrt{3}}
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  3. #3
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    No, you gave me the answer. I just needed to understand how to determine the function value for sine. I got it now thank you very much!
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