find, for 0=<A=<360

(A:tan^(3A)=tanA)

i stuck at tan^3 and tanA.

find 6tan^2(A)-4sin^2(A)=1 , 0=<A=<360

i stuck at 6tan^2(A).

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- September 10th 2008, 05:06 AMsanikuitrigo equation
find, for 0=<A=<360

(A:tan^(3A)=tanA)

i stuck at tan^3 and tanA.

find 6tan^2(A)-4sin^2(A)=1 , 0=<A=<360

i stuck at 6tan^2(A). - September 10th 2008, 05:19 AMmr fantastic
- September 10th 2008, 05:27 AMmr fantastic
- September 10th 2008, 06:01 AMsanikui
question 1, i know do liaw....thx ~!

- September 10th 2008, 06:02 AMsanikui
O.o

For question 2, i know the answer A is 30*, 150*, 210*, 330*.

But the problem is didnt how to do.

Thx for helping~!V^^ - September 10th 2008, 01:28 PMmr fantastic
- September 11th 2008, 04:46 AMsanikui
cos^2(A)=3/4 this undefined.

- September 11th 2008, 05:07 AMmr fantastic