I need help with the following:
For some right triangle, sin x = 3/5. find cos x as a fraction
for some right triangle, tan x = 24/7. Find csc x as fraction
Thanks
a right traingle with lengths 3 and 5, where 5 is the hypotenuse, must be a 3, 4, 5 or similarly proportioned triangle. so cosx = 4/5
You could have also solved this by doing $\displaystyle \sqrt{5^2-3^2}=4$
remember tan is opposite over adjacent for the second one.