tan(arcsin x)
sin(arctan x)
Please Help, I have no idea what to do.
Let $\displaystyle \arcsin x = \theta \Rightarrow x = \sin \theta$.
$\displaystyle \tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{x}{\sqrt{1 - x^2}}$.
Therefore $\displaystyle \tan (\arcsin x) = \frac{x}{\sqrt{1 - x^2}}$.
Only the positive root is required (why?).
Try the second one now.