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Math Help - Math Trig. Help!

  1. #1
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    Math Trig. Help!

    An aircraft flies from its base 200km on a bearing 162 degrees, then 350 km on a bearing 260 degrees, and then returns directly to base. Calculate the length and bearing of the return journey!!!

    Please help me!!!!!
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  2. #2
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    Quote Originally Posted by <3<3 View Post
    An aircraft flies from its base 200km on a bearing 162 degrees, then 350 km on a bearing 260 degrees, and then returns directly to base. Calculate the length and bearing of the return journey!!!

    Please help me!!!!!
    Draw a diagram, it does half the question for you.

    To work out the length it travels, use the cosine rule. a^2 = b^2 + c^2 - 2bc\cos A, where:
    • a,b,c are your lengths.
    • A is the angle opposite to the side a.
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  3. #3
    Junior Member shinhidora's Avatar
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    As I replied to your other topic!

    If you draw that out, you should en up with a triangle...

    'A' being your base
    'B' being your first point where you change bearing
    'C' being the point where you return to your base

    = 180 - 162 = 18 degrees
    b = 360 - 260 = 100 degrees
    c = 180 - 18 - 100 = 62 degrees

    AB = 200km
    BC = 350 km
    CA = X

    you need to find x I drew it out in paint but it ended up horribly so nvm

    You know how to do it now? Or are the formulae what you're looking for?
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