An aircraft flies from its base 200km on a bearing 162 degrees, then 350 km on a bearing 260 degrees, and then returns directly to base. Calculate the length and bearing of the return journey!!!
Please help me!!!!!
As I replied to your other topic!
If you draw that out, you should en up with a triangle...
'A' being your base
'B' being your first point where you change bearing
'C' being the point where you return to your base
â = 180 - 162 = 18 degrees
b = 360 - 260 = 100 degrees
c = 180 - 18 - 100 = 62 degrees
AB = 200km
BC = 350 km
CA = X
you need to find x I drew it out in paint but it ended up horribly so nvm
You know how to do it now? Or are the formulae what you're looking for?