rectangle a,b,c,d. a to b =40km a to c=140km what is distance a to d?
what is area covered by a,d,c?
402 +1402 =
1600+19600=
21200
√21200=
20√53
how do i work with this?
If you draw reactangle ABCD, AC=hypotenuse of triangle ADC=140 km
and CD=AB=40 km.
In triangle ADC,
$\displaystyle
AD^2 + CD^2 = AC^2$
$\displaystyle AD^2 + 40^2 = 140^2$
$\displaystyle AD^2 = 140^2 - 40^2$
$\displaystyle AD = \sqrt{19600 - 1600}$
$\displaystyle AD = \sqrt{18000}$
$\displaystyle AD = \sqrt{5\times 3^2 \times 2^2 \times 10^2}$
$\displaystyle AD = 60 \sqrt{5}$
$\displaystyle AD = 60 \times 2.236$
$\displaystyle AD = 134.164 \;km$
Area covered by triangle ADC;
$\displaystyle =\frac{base \times height}{2}$
$\displaystyle =\frac{40 \times 134.164}{2}$
$\displaystyle =2683.28\; km^2$
If your question is not clear you can't expect to get a good answer.
Let ad = x. Then x^2 + 40^2 = 140^2 => .....
By the way, don't ask for help in Live Chat. It clearly says that Live Chat is for small talk.