rectangle a,b,c,d. a to b =40km a to c=140km what is distance a to d?

what is area covered by a,d,c?

402 +1402 =

1600+19600=

21200

√21200=

20√53

how do i work with this?

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- Sep 7th 2008, 10:28 AMinneedofhelp!ariiefind the hyp.
rectangle a,b,c,d. a to b =40km a to c=140km what is distance a to d?

what is area covered by a,d,c?

402 +1402 =

1600+19600=

21200

√21200=

20√53

how do i work with this? - Sep 7th 2008, 10:50 AMShyam
- Sep 7th 2008, 11:10 AMinneedofhelp!ariie
no the diagonal (hypotenuse) is A to D

A to B is 40km

A to C is 140km

the diagonal is always longest so cannot be 134 - Sep 7th 2008, 11:38 PMmr fantastic
If your question is not clear you can't expect to get a good answer.

Let ad = x. Then x^2 + 40^2 = 140^2 => .....

By the way, don't ask for help in Live Chat. It clearly says that Live Chat is for small talk.