Thread: determining Sin x as Cos x = sqrt 3/2

Hello I need help in determining Sin x as Cos x = sqrt 3/2.

What should I know to be able to do this. and how?
I would like a fully detailed explanation if possible.

Hello, Meowet!

We have: .

is a in a right triangle with: .

The triangle looks like this:

Code:

                        *
                     *  *
              2   *     *
               *        *
            *           *
         * x            *
      *  *  *  *  *  *  *
              √3

Pythagorus says: .

So we have: .

. . Hence: .


Therefore: .