Hello I need help in determining Sin x as Cos x = sqrt 3/2. What should I know to be able to do this. and how? I would like a fully detailed explanation if possible.
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Hello, Meowet! We have: . is a in a right triangle with: . The triangle looks like this: Code: * * * 2 * * * * * * * x * * * * * * * * √3 Pythagorus says: . So we have: . . . Hence: . Therefore: .
* * * 2 * * * * * * * x * * * * * * * * √3
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