cos3X=sinX

Find X, 0 degree < x < 360 degree

Thanks in advance

Printable View

- Sep 6th 2008, 02:22 AMose90Solving trigo
cos3X=sinX

Find X, 0 degree < x < 360 degree

Thanks in advance - Sep 6th 2008, 02:43 AMmr fantastic
There's the hard way and the easy way. Personally I like the easy way best:

From the complementary angle formulae: .

**Case 1:**where n is an integer.

Solve for x and substitute appropriate values of n to get all values of x satisfying the given domain.

**Case 2:**where n is an integer.

Solve for x and substitute appropriate values of n to get all values of x satisfying the given domain. - Sep 6th 2008, 03:01 AMose90
Thank you very much!