ABC-acute triangle. prove that sinA+sinB>cosA+cosB+cosC thanks
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Originally Posted by ely_en ABC-acute triangle. prove that sinA+sinB>cosA+cosB+cosC thanks Proof: since A, B and C are between 0 and both sides of the inequality are positive. now: Proof: by
Originally Posted by NonCommAlg Proof: since A, B and C are between 0 and both sides of the inequality are positive. now: Proof: by could you tell me how did you get from , please? Thank you very much
Hello, Originally Posted by ely_en could you tell me how did you get from , please? Thank you very much Are you familiar with ? But we know that Therefore
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