I dont know how to find the side! Problem: a= 16 c= 12 B= 63degrees I know the formula to use afterwards. a^2=b^2 + c^2 - 2bc COS A
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Originally Posted by topaz192 I dont know how to find the side! Problem: a= 16 c= 12 B= 63degrees I know the formula to use afterwards. a^2=b^2 + c^2 - 2bc COS A you're supposed to use the formula to find the side. $\displaystyle b^2 = (16)^2 + (12)^2 - 2(16)(12) \cos 63$ use that to find the other side, b
Originally Posted by topaz192 I dont know how to find the side! Problem: a= 16 c= 12 B= 63degrees I know the formula to use afterwards. a^2=b^2 + c^2 - 2bc COS A Try this version of the formula: $\displaystyle b^2=a^2+c^2-2ac\cos B$ It's the exact same thing with the letters rearranged. [EDIT] Dang he beat me, lol.
lol yea i found a tutorial online thanks for your time though!
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