A central angle of a circle with radius 10 has a measure of 1.35 radians. The secant line between the end points of the arc of the angle divides the sector swept by the arc into two regions, one a triangle and the other bounded by the secant and the arc. What is the area of the region bounded by the secant and the arc?
This is what I have so far:
A1=1/2*r squared*theta, so A1=1/2*10 squared*1.35 rad=67.5
A2=1/2*a*b*sin theta, so A2=1/2*10*?*sin ?
A=A1-A2, so 67.5-??
*I'm not sure how to find b or how about sin theta in A2.... ?
(My scanner isn't working properly so I drew the picture that correlates to the problem below)