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**accordry** A central angle of a circle with radius 10 has a measure of 1.35 radians. The secant line between the end points of the arc of the angle divides the sector swept by the arc into two regions, one a triangle and the other bounded by the secant and the arc. What is the area of the region bounded by the secant and the arc?

This is what I have so far:

A1=1/2*r squared*theta, so A1=1/2*10 squared*1.35 rad=67.5

A2=1/2*a*b*sin theta, so A2=1/2*10*?*sin ?

A=A1-A2, so 67.5-??

*I'm not sure how to find b or how about sin theta in A2.... ?