prove the ff identities sec x + 1 / tan x - tan x / sec x -1 = 0 1-sinx/1+sinx = (secx-tanx)^2 thanks
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Hi, Originally Posted by eepyej prove the ff identities sec x + 1 / tan x - tan x / sec x -1 = 0 Now, expand in the numerator thanks to this formula : And remember that 1-sinx/1+sinx = (secx-tanx)^2 Multiply by
Hello, eepyej! Another approach . . . Prove: . Multiply the first fraction by . . . .
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