# Math Help - find the triangle

1. ## find the triangle

Find all solutions for each triangle.

A = 30
a = 4
b = 8

4 / 30 = 8 / SIN B

4 SIN B = 8 ( SIN30 )

SIN B = 8 (SIN 30) / 4 = 1

Did I do that right?
I know there is only one solution.

2. Yes, you are right.
$
=\frac{4}{sin30}= \frac{8}{sinB}
$

$
sinB=1
$

$
B=90
$

Now, in right triangle, right angled at B,

$
c=\sqrt{8^2-4^2}
$

$
c=\sqrt{48}=\;4\sqrt{3}
$

$
C=180-(90+30)=60
$

3. where did 90 come from?

i get everything else.

4. Originally Posted by topaz192
where did 90 come from?

i get everything else.
90 degrees is the angle whose sine is 1.

5. Ooooh Ok duh. lol thnks!