# find the triangle

• Aug 27th 2008, 05:58 PM
topaz192
find the triangle
Find all solutions for each triangle.

A = 30
a = 4
b = 8

4 / 30 = 8 / SIN B

4 SIN B = 8 ( SIN30 )

SIN B = 8 (SIN 30) / 4 = 1

Did I do that right?
I know there is only one solution.
• Aug 27th 2008, 06:12 PM
Shyam
Yes, you are right.
$
=\frac{4}{sin30}= \frac{8}{sinB}
$

$
sinB=1
$

$
B=90
$

Now, in right triangle, right angled at B,

$
c=\sqrt{8^2-4^2}
$

$
c=\sqrt{48}=\;4\sqrt{3}
$

$
C=180-(90+30)=60
$
• Aug 27th 2008, 06:16 PM
topaz192
where did 90 come from?

i get everything else.
• Aug 27th 2008, 06:18 PM
icemanfan
Quote:

Originally Posted by topaz192
where did 90 come from?

i get everything else.

90 degrees is the angle whose sine is 1.
• Aug 27th 2008, 06:20 PM
topaz192
Ooooh Ok duh. lol thnks!