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Math Help - Quickie! Ambiguous Cases

  1. #1
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    [ 1 more question ] Quickie! Ambiguous Cases

    After determing if a triangle is either case 1: a < 90 or case 2: a > 90.

    In order to find how many solutions (if there is any) there is

    EX:

    A= 30 a= 13 c=26

    Its case 1. Since its less than 90. After this do I do 26SIN(30)=____

    To find how many solutions?
    I know the guidelines for the solutions...
    Last edited by topaz192; August 27th 2008 at 05:41 PM.
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  2. #2
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    Quote Originally Posted by topaz192 View Post
    After determing if a triangle is either case 1: a < 90 or case 2: a > 90.

    In order to find how many solutions (if there is any) there is

    EX:

    A= 30 a= 13 c=26

    Its case 1. Since its less than 90. After this do I do 26SIN(30)=____

    To find how many solutions?
    I know the guidelines for the solutions...
    There are 2 solutions... meaning 2 lengths for b, 2 angles for b, and 2 angles for c. I'm not really sure I really understand all of what you are saying, though.
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  3. #3
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    Lol I dont either after reading. I guess I just dont understand how you know how to find how many solutions there are? How did you find it?
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  4. #4
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    26\sin(30^{\circ}) = 13

    there is only one solution, and it's a right triangle.
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  5. #5
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    Ok I get it now. Its one solution because its both 13 , right?

    I kept thinking I was doing it wrong trying to get two solutions! lol
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  6. #6
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    How do you find it if its an angle - angle - side??
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  7. #7
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    EX:
    A= 58
    C= 94
    b= 17

    my teacher didnt go over ANYTHING like that!
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  8. #8
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    Here,
    <br />
a=13,\; and,\;<br />
b.sinA=(26).(sin30)=13<br />

    <br />
So,\; a=b.sinA<br />

    So, there is only one solution, one triangle.
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  9. #9
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    Quote Originally Posted by topaz192 View Post
    EX:
    A= 58
    C= 94
    b= 17

    my teacher didnt go over ANYTHING like that!
    When you have two angles of a triangle you can determine the third. In your example, which I quoted above, B = 180 - A - C = 180 - 58 - 94 = 28. Then you have 17/sin(28) = c/sin(94) = a/sin(58).
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  10. #10
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    So itd just be no solutions. since itll be less than the bsinA
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