Hello,
That's pretty weird... Is it and ?
If so, then remember this property :
Therefore
If x = e^3t & y = e^t, where e is exponential number
Find equation of y in terms of x?
Ans: y^3 = 3x
These are my steps:
x = e^3t
(or) e^(ln x) = e^3t
(or) ln x = 3t
(or) t = (ln x)/3 ------(i)
y = e^t
(or) e^(ln y) = e^t
(or) ln y = t
(or) ln y = (ln x)/3 ------Using (i)
What to do after this???
~~~~~~~~~~~~~~~~~~~
EDIT: Question NULL & VOID
Hello Moo.
The original question was a mechanics question. It stated:
A body starts from origin with velocity V = (e^3t)i + (e^t)j. Then find the equation of trajectory of the body?
Ans: y^3 = 3x
i - unit vector along x-axis
j - unit vector along y-axis
Was my interpretation of the question wrong?
EDIT: I messed up. dx/dt = e^3t and dy/dt = e^t.
Which gives x = e^(3t)/3 and y = e^t
And using the obvious property which Moo stated(instead of doing the rubbish I did by taking natural log), x = (y^3)/3