How would you find the period of y=-4sin(pi/3)x ?
-sorry, i dont know how to put the pi sybol in so I wrotwe it
-thanks for any help, J.T.
Hi !
Welcome in the forum ! There's the latex in here, just do $\displaystyle \pi$ or $\displaystyle y=-4 \sin \left(\frac{\pi}{3} x \right)$
See here : http://www.mathhelpforum.com/math-help/latex-help/ for more codes.
For your problem. The period T is defined such that f(x+T)=f(x).
So here $\displaystyle f(x+T)=-4 \sin \left(\frac{\pi}{3} (x+T) \right)$
You know that the sine function is $\displaystyle \underline{2 \pi}$ periodic. So it would be nice to find T such that we get this $\displaystyle 2 \pi$
Develop f(x+T) :
$\displaystyle \begin{aligned} f(x+T) &=-4 \sin \left(\frac{\pi}{3} (x+T) \right) \\
&=\underbrace{-4 \sin (\tfrac{\pi}{3} x}_{\text{this is f(x)}}+\tfrac{\pi}{3} T ) \end{aligned}$
So find T such that $\displaystyle \frac{\pi}{3} T=2 \pi$ and you're done