finding the period of an equation

How would you find the period of y=-4sin(pi/3)x ?

-sorry, i dont know how to put the pi sybol in so I wrotwe it

-thanks for any help, J.T.

Given the general periodic function: $y = A\sin(B(x + C)) + D$

The period is given by: $\frac{2\pi}{B}$

Hi !

Quote:

Originally Posted by jem7vwhjt

How would you find the period of y=-4sin(pi/3)x ?

-sorry, i dont know how to put the pi sybol in so I wrotwe it

-thanks for any help, J.T.

Welcome in the forum ! There's the latex in here, just do $\pi$ or $y=-4 \sin \left(\frac{\pi}{3} x \right)$
See here : http://www.mathhelpforum.com/math-help/latex-help/ for more codes.

For your problem. The period T is defined such that f(x+T)=f(x).

So here $f(x+T)=-4 \sin \left(\frac{\pi}{3} (x+T) \right)$

You know that the sine function is $\underline{2 \pi}$ periodic. So it would be nice to find T such that we get this $2 \pi$

Develop f(x+T) :
$\begin{aligned} f(x+T) &=-4 \sin \left(\frac{\pi}{3} (x+T) \right) \\<br /> &=\underbrace{-4 \sin (\tfrac{\pi}{3} x}_{\text{this is f(x)}}+\tfrac{\pi}{3} T ) \end{aligned}$

So find T such that $\frac{\pi}{3} T=2 \pi$ and you're done (Wink)

thank you