Thread: trigonometry triangle

Sorry, Im in a rush I didnt draw a triangle this time [lol] but i have to find the area of this triangle

b=146.2 c= 209.3 A=62.2

I did:

Area= 1/2(209.3)(146.2)SiN(62.6) = 13533.94

It looks wrong to me though, since the number appears large...

Originally Posted by topaz192

Sorry, Im in a rush I didnt draw a triangle this time [lol] but i have to find the area of this triangle

b=146.2 c= 209.3 A=62.2

I did:

Area= 1/2(209.3)(146.2)SiN(62.2) = 13533.94

It looks wrong to me though, since the number appears large...

But the lengths of the sides are large too =]

I find it to be the same

Sorry! Typos! Lol

Oh ok thank you!

I used Heron's formula here, but i get the same answer as you do:

Solving Triangle Methods

Same relation as last problem. (A,B,C) = (1,2,3)