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Math Help - Angle of Refraction

  1. #1
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    Angle of Refraction

    What exactly do i do in a problem like this? It threw me off when I saw snell's law.



    In snell's law, -0- is the angle of incidence, -0-(2) is the angle of refraction, and n is the index of refraction. The index of refraction for a diamond is 2.42. if a beam of light strikes a diamond at an angle of incidence of 60 degrees, find the angle of refraction...

    Can some one list the steps, [ not the answer! ] so I can get an understanding of how to work such problems please?
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  2. #2
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    Hello, topaz192!

    \frac{\sin\theta_i}{\sin\theta_r} \:=\:n

    In Snell's law, \theta_i is the angle of incidence, \theta_r is the angle of refraction,
    and n is the index of refraction.

    The index of refraction for a diamond is 2.42.
    If a beam of light strikes a diamond at an angle of incidence of 60,
    find the angle of refraction.

    We are given: . \theta_i = 60^o,\;n = 2.42

    Substitute into the law: . \frac{\sin 60^o}{\sin\theta_r} \:=\:2.42 \quad\Rightarrow\quad \sin\theta_r \:=\:\frac{\sin60^o}{2.42}\:=\:0.357861737

    Therefore: . \theta_r \;=\;\sin^{-1}(0.357861737) \;=\;20.96893592^o \;\approx\;\boxed{21^o}

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  3. #3
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    Omigosh. It was soo much simplier than I thought.

    Thanks so much!

    I understand. I just need to look up what index of refraction is and what not
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