1. ## Trigonometric Equaiton Help Please!

Find the angle in degrees

0.342Dcosx + hcos(squared)x = 16D(squared) / V(squared)

V = 60
D = 80
h = 2

2. Originally Posted by nee
Find the angle in degrees

0.342Dcosx + hcos(squared)x = 16D(squared) / V(squared)

V = 60
D = 80
h = 2

Is it (16*D)^2 or 16*(D^2)?

3. The way it's written in the text is 16D(squared).

4. Originally Posted by nee
The way it's written in the text is 16D(squared).

Ok, which one of my 2 ways would you interpret that?

5. Originally Posted by lewisb13
Ok, which one of my 2 ways would you interpret that?
@ nee: meaning, was it $16D^2$ or $(16D)^2$

6. exactly

7. So you've got 2x^2+27.36x^2-256/9=0
Here we are letting x = cos x
Use the quadratic equation. Youll get 2 numbers. Probably one positive and one negative.

FOR EXAMPLE you get 5 and -16

5 = cos x
-16 = cos x

Solve for x.

8. x = -14.6508 or x = .97075

9. 13.892 degrees

10. Thanks alot, I'll give it a try!

11. I keep getting -12.55 and -1.133 which don't give me an angle!?

12. Did you solve the quadratic? Or are those ^^^^ the numbers you got while solving the quadratic?

13. Ya I used

and put the values into:

I end up with

x = -27.36 +or- 22.83 / 4

which gives me

12.55 and -1.133