Thread: Trigonometric Equaiton Help Please!

Find the angle in degrees

0.342Dcosx + hcos(squared)x = 16D(squared) / V(squared)

V = 60
D = 80
h = 2

Originally Posted by nee

Find the angle in degrees

0.342Dcosx + hcos(squared)x = 16D(squared) / V(squared)

V = 60
D = 80
h = 2

Is it (16*D)^2 or 16*(D^2)?

The way it's written in the text is 16D(squared).

Originally Posted by nee

The way it's written in the text is 16D(squared).

Ok, which one of my 2 ways would you interpret that?

Originally Posted by lewisb13

Ok, which one of my 2 ways would you interpret that?

@ nee: meaning, was it or

exactly

So you've got 2x^2+27.36x^2-256/9=0
Here we are letting x = cos x
Use the quadratic equation. Youll get 2 numbers. Probably one positive and one negative.

FOR EXAMPLE you get 5 and -16

5 = cos x
-16 = cos x

Solve for x.

x = -14.6508 or x = .97075

13.892 degrees

Thanks alot, I'll give it a try!

I keep getting -12.55 and -1.133 which don't give me an angle!?

Did you solve the quadratic? Or are those ^^^^ the numbers you got while solving the quadratic?

Ya I used



and put the values into:



I end up with

x = -27.36 +or- 22.83 / 4

which gives me

12.55 and -1.133