Originally Posted by
nee Ok I think I got it:
sec(squared)xtanx = 2tanx
sec(squared)xtanx - 2tanx = 0
sec(squared)xtanx - tanx - tanx = 0
tanx(sec(squared)x - 2) = 0
tanx = 0 or sec(squared)x - 2 = 0
sec(squared)x = 2
secx = (squareroot)2
therefore:
a(squared) + b(squared) = c(squared)
1(squared) + b(squared) = ((squareroot)2)(squared)
1 + b(squared) = 2
1 + 1 = 2 (if I'm not mistaken)
therefore tanx = + or - 1
therefore solution set:
{0. 45, 135, 180, 225, 315)
correct me if me wrong please
NEE!!