16^2x/8^x+2=32^x-4 20-6= 5x-5x...and the x's are cancelling out..
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Originally Posted by nithu 16^2x/8^x+2=32^x-4 20-6= 5x-5x...and the x's are cancelling out.. you need to type more clearly, i am not sure what you are asking. please use parentheses and the proper conventions is this what you mean? $\displaystyle \frac {16^{2x}}{8^x + 2} = 32^x - 4$
yes..thats how the question looks like...
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