# i need help solving for x

• Aug 23rd 2008, 07:18 PM
nithu
i need help solving for x
16^2x/8^x+2=32^x-4

20-6= 5x-5x...and the x's are cancelling out..
• Aug 23rd 2008, 07:27 PM
Jhevon
Quote:

Originally Posted by nithu
16^2x/8^x+2=32^x-4

20-6= 5x-5x...and the x's are cancelling out..

you need to type more clearly, i am not sure what you are asking. please use parentheses and the proper conventions

is this what you mean? $\frac {16^{2x}}{8^x + 2} = 32^x - 4$
• Aug 24th 2008, 10:10 AM
nithu
yes..thats how the question looks like...